Mathematics Profesor

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Other Artist Anna Gilbert is a Musician of United States.

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Statistic Problem

1. Known the number of ball n(s) = 100 Ask: The change take a ball with number divisible by 5 but not divisible by 3 if taken randomly. Answer: For example A = ball with number divisible by 5 but not divisible by 3 n(A) = 14, namely 5, 10, 20, 25, 35, 40, 50, 55, 65, 70, 80, 85, 95 and 100 P(A) = n(A)/n(s) = 14/100 = 7/50 2. Known: One badminton team consist of 5 members, will decide 2 people play a single players, and 2 pairs to play double. Ask: How many option can be made. First Way Solution: For example 5 people of badminton team are A, B, C, D, and E. Then we choose A and B to play single. Option Single Double 1 A, B CD, AE 2 A, B CE, AD 3 A, B  DE, AC 4 A, B CD, BE 5 A, B CE, BD 6 A, B DE, BC The option number when A and B choose as single player are 6 option. The way to choose player as single player are 10, namely AB, AC, AD, AE, BC, BD, BE, CD, CE, and DE. From one option of single player will make 6 option so for all way to choose si...
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Cube and Tube Formula

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Cube: Cube Volume V = a 3                              (1) where V = volume (m 3  , ft 3  ) a = side (m, ft) Surface Area Ao = 6 a 2   (1b) where Ao = surface area (m 2 , ft 2 ) Diagonal d = a 3 1/2  (1c) where d = innside diagonal (m, ft) Cuboid Tube Volume V = a b c                                    (2) where: V = volume of solid (m 3  , ft 3  ) a = length of rectangular prism (m, ft) b = width of rectangular prism (m, ft) c = height of rectangular prism (m, ft) Diagonal d = (a 2 + b 2   + c 2 ) 1/2                    (2b) Surface Area Ao = 2 (a b + a c + b c)                 (2c) where Ao = surface area of solid (m 2 , ft 2  ) Par...
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Mathematic Principle

The basic problems of the sciences and engineering fall broadly into three categories: Steady state problems. In such problems the configuration of the system is to be determined. This solution does not change with time but continues indefinitely in the same pattern, hence the name “steady state.” Typical chemical engineering examples include steady temperature distributions in heat conduction, equilibrium in chemical reactions, and steady diffusion problems. Eigenvalue problems. These are extensions of equilibrium problems in which critical values of certain parameters are to be determined in addition to the corresponding steady-state configurations. The determination of eigenvalues may also arise in propagation problems. Typical chemical engineering problems include those in heat transfer and resonance in which certain boundary conditions are prescribed. Propagation problems. These problems are concerned with predicting the subsequent behavior of a system from a knowledge of the in...
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